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What are the boiling points and freezing points of a 24.7 m solution of napthalene in benzene (the solvent)?

Given that for benzene: boiling point= 80.1 C Kb= 2.53 C . m^-1 freezing point= 5.5 C Kf= 5.12 C . m^-1 I got: 86.4 and -7.1...am I right?

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  1. delta T = 24.7 x 2.53 = 62.49 boiling point = 62.49 + 80.1 =142.6 °C delta T = 24.7 x 5.12 = 126.5 freezing point = 5.5 - 126.5 =- 121 °C
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